站长资源网络编程
PHP响应post请求上传文件的方法
简介本文实例讲述了PHP响应post请求上传文件的方法。分享给大家供大家参考，具体如下：function send_file($url, $post = '', $file = '')
$data .= '--' . $mime_boundary . $eol;
$data .= 'Content-Disposition: form-data; name=' . $file [name] . '; filename=' . $file [filename] . $eol;
$data .= 'Content-Type: text/plain' . $eol;
$data .= 'Content-Transfer-Encoding: binary' . $eol . $eol;
$data .= $file [filedata] . $eol;
$data .= "--" . $mime_boundary . "--" . $eol . $eol;
$params = array ('http' => array ('method' => 'POST', 'header' => 'Content-Type: multipart/form-data;boundary=' . $mime_boundary . $eol, 'content' => $data ) );
$ctx = stream_context_create ( $params );
$response = file_get_contents ( $url, FILE_TEXT, $ctx );
return $response;
}
希望本文所述对大家PHP程序设计有所帮助。